5cm
7cm
10cm
15cm
Correct answer is C
\(\frac{1}{2}(a+b)\times h = 105cm^2\\
\frac{1}{2}(9+12)\times h = 105\\
h = \frac{105 \times 2}{21} = 10cm\)
Simplify \(\frac{1}{1-x} + \frac{2}{1+x}\)
\(\frac{x+3}{1-x^2}\)
\(\frac{x-3}{1+x^2}\)
\(\frac{3-x}{1-x^2}\)
\(\frac{3-x}{1+x^2}\)
Correct answer is C
\(\frac{1}{1-x} + \frac{2}{1+x}\\
\frac{1+x+2-2x}{(1-x)(1+x)} = (\frac{3-x}{1-x^2})\)
For what values of x is the expression \(\frac{3x-2}{4x^2+9x-9}\) undefined?
\(\frac{-3}{4} \hspace{1mm}or \hspace{1mm}3\)
\(\frac{-2}{3} \hspace{1mm}or \hspace{1mm}-3\)
\(\frac{2}{3} \hspace{1mm}or \hspace{1mm}3\)
\(\frac{3}{4} \hspace{1mm}or \hspace{1mm}-3\)
Correct answer is D
The equation \(\frac{3x - 2}{4x^2 + 9x - 9}\) is undefined when the denominator = 0.
\(4x^2 + 9x - 9 = 0\)
\(4x^2 + 12x - 3x - 9 = 0\)
\(4x(x + 3) - 3(x + 3) = 0\)
\((4x - 3)(x + 3) = 0\)
x = \(\frac{3}{4}\) or x = -3.
In the diagram, SQ is a tangent to the circle at P, XP||YQ, ∠XPY = 56o and ∠PXY = 80o.Find angle PQY
34o
13.36o
44o
46o
Correct answer is A
< XYQ = 180° - (80° + 56°)
= 44°
< PYQ = 56° (alternate angles, XP||YQ)
< QPY = 90°
< PQY = 180° - (90° + 56°)
= 34°
Which of the following is represented by the above sketch?
y = x2 + x - 6
y = x2 - x - 6
y = x2 - x + 6
y = x2 + x + 6
Correct answer is B
From the graph, the zeros of the equation exist at x = -2 and x = 3
\(\therefore\) (x + 2) = 0 and (x - 3) = 0
\(\implies (x + 2)(x - 3) = 0\)
\(x^2 - 3x + 2x - 6 = 0\)
\(x^2 - x - 6 = 0\) is the equation represented on the graph.
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