6
5
4
-5
Correct answer is A
\(log2 = 0.3010\hspace{1mm}given\\ log2^y = 1.8062\\ ∴ ylog2 = 1.8062\\ y=\frac{1.8062}{logy}=\frac{1.8062}{0.3010}=6\)
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