WAEC Mathematics Past Questions & Answers - Page 195

971.

The square root of a number is 2k. What is half of the number

A.

\(\sqrt{\frac{k}{2}}\)

B.

\(\sqrt{k}\)

C.

\(\frac{1}{2}k^2\)

D.

2k2

Correct answer is D

Let the number be x.

\(\sqrt{x} = 2k \implies x = (2k)^2\)

= \(4k^2\)

\(\frac{1}{2} \times 4k^2 = 2k^2\)

972.

From the Venn Diagram below, find Q' ∩ R.

A.

(e)

B.

(c, h)

C.

(c, g, h)

D.

(c, e, g, h)

Correct answer is C

Q' ∩ R Q' = U - Q Q' = {a, b, c, d, g, h, i} R = {c, e, h, g} Q' ∩ R = {c, h, g}

973.

From the Venn diagram below, how many elements are in P∩Q?

A.

1

B.

2

C.

4

D.

6

Correct answer is B

P \(\cap\) Q = {f, e} = 2

974.

If \(P = \sqrt{QR\left(1+\frac{3t}{R}\right)}\), make R the subject of the formula.

A.

\(R = \frac{3Qt}{P^2 - Q}\)

B.

\(R = \frac{P^2 – 3t}{Q+1}\)

C.

\(R = \frac{P^2 + 3t}{Q - 1}\)

D.

\(R = \frac{P^2-3Qt}{Q}\)

Correct answer is D

No explanation has been provided for this answer.

975.

In a ∆ XYZ, /YZ/ = 6cm YXZ = 60o and XYZ is a right angle. Calculate /XZ/in cm, leaving your answer in surd form

A.

2√3

B.

4√3

C.

6√3

D.

12√3

Correct answer is B

\(sin \theta = \frac{opp}{hyp}\\
sin 60^o = \frac{|YZ|}{|XZ|}=\frac{6}{P}\\
P sin 60^o = 6\\
P = \frac{6}{sin60^o}\\
=\frac{6}{\sqrt{\frac{3}{2}}}=4\sqrt{3}\)