Out of 60 members of an Association, 15 are Doctors and 9 are Lawyers. If a member is selected at random from the Association, what is the probability that the member is neither a Doctor Nor a Lawyer

A.

\(\frac{3}{5}\)

B.

\(\frac{9}{10}\)

C.

\(\frac{3}{20}\)

D.

\(\frac{1}{4}\)

Correct answer is A

Member that are neither doctors nor lawyers = 60-(15+9)=36
Probability (Not doctors ad not lawyers) \(=\frac{36}{60}\\
=\frac{6}{10}=\frac{3}{5}\)