The length of a piece of stick is 1.75 m. A boy measured it as 1.80 m. Find the percentage error
4\(\frac{4}{7}\)
2\(\frac{6}{7}\)
2\(\frac{7}{9}\)
4\(\frac{7}{9}\)
Correct answer is B
Error = 1.80 - 1.75 = 0.05
%error = \(\frac{error}{original length}\)
= \(\frac{0.05 * 100}{1.75}\)
= 2.85 or 2\(\frac{6}{7}\)
Three boys shared D 10,500.00 in the ratio 6:7:8. Find the largest share.
4000
5000
4500
3500
Correct answer is A
Total proportion is 6+7+8 = 21
\(\frac{6 * 10500}{21}\) = 3000
\(\frac{7 * 10500}{21}\) = 3500
\(\frac{8 * 10500}{21}\) = 4000
The largest share is 4000
If a = 3 and b = -7, find the value of \(\frac{5b+(a+b)^2}{(a-b)^2}\)
0.51
0.91
-0.19
-0.51
Correct answer is C
\(\frac{5b+(a+b)^2}{(a-b)^2}\)
= \(\frac{5 * -7 +(3+ -7)^2}{(3- -7)^2}\)
= \(\frac{-35 + 16}{10^2}\)
= \(\frac{-19}{100}\) or -0.19
\(\frac{3n}{2p^2}\)
\(\frac{2n}{3p^2}\)
\(\frac{2n}{3p}\)
\(\frac{3n^2}{2p^2}\)
Correct answer is A
M = \(\frac{nk}{p^2}\)
k → \(\frac{mp^2}{n}\) = \(\frac{3x1^2}{2}\)
k = \(\frac{3}{2}\)
: m = \(\frac{3xn}{2p^2}\)
Find the 17term of the Arithmetic Progression (A.P):-6,-1,4
-91
-86
74
79
Correct answer is C
common difference d = -1 - [-6] → -1 + 6
d = 5; a = -6
T\(_n\) = a + (n-1)d
: T\(_{17}\) = -6 + (17 - 1) 5
→ -6 + (16)5
→ -6 + 80 = 74