WAEC Mathematics Past Questions & Answers - Page 161

801.

If the pass mark was 4. What percentage of the pupils failed the test?

A.

20.0%

B.

37%

C.

62.5%

D.

80.0%

Correct answer is A

No. of pupils that failed = 1 + 3 + 4 + 8

% failed = \(\frac{8}{40} \times 100\)% = 20.0%

802.

How many pupils took the test?

A.

36

B.

38

C.

39

D.

40

Correct answer is D

No. of pupils = 1 + 3 + 4 + 7 + 8 + 6 + 6 + 4 + 1 = 40

803.

In the diagram, PQR is a straight line, QRST is a parallelogram, < TPQ = 72o and < RST = 126o. What type of triangle is \(\bigtriangleup\) PQT?

A.

An equilateral triangle

B.

A right-angled triangle

C.

An isosceles triangle

D.

A scalene triangle

Correct answer is C

No explanation has been provided for this answer.

804.

In the diagram, the two circles have a common centre O. If the area of the larger circle is 100\(\pi\) and that of the smaller circle is 49\(\pi\), find x

A.

2

B.

3

C.

4

D.

6

Correct answer is B

area of larger circle = 100\(\pi\)

\(\pi r^2 = 100\pi\)

R2 = 100

R = 10(Radius)

Area of smaller circle = \(49 \pi\)

\(\pi r^2 = 49\pi\)

r2 = 49

r = 7(radius)

Since R = x + r

x = R - r

x = 10 - 7 = 3

805.

In the diagram, P, Q and R are three points in a plane such that the bearing of R from Q is 110o and the bearing of Q from P is 050o. Find angle PQR.

A.

60o

B.

70o

C.

120o

D.

160o

Correct answer is C

Q1 = 50(alternate angle)

Q2 = 180o - 110o (straight line angle)

Q2 = 70

PQR = Q1 + Q2

= 50o + 70o

= 120o