2
3
4
6
Correct answer is C
Let normal working hour = x
let overtime = y
after 10 hours = N31.00
1 x 2.50x + 4y = 31
4 x x + y = 10
2.50x + 4y = 31
- 4x + 4y = 30
----------------
-1.5x = -9
x = 6; x + y = 10
6 + y = 10
y = 10 - 4
y = 4hrs for over time
Find the value of a if log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030
4.0
2.0
1.6
0.0
Correct answer is C
log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030
log (a x a\(^2\)) = 0.9030
log a\(^3\) = 0.9030
a\(^3\) = 10^.9030(antilogarithm table)
a\(^3\) = 7.998
a = 3\(\sqrt{7.998}\)
a = 1.6
The bearing of a point P from another point Q is 310o. If |PQ| = 200m, how far west of Q is P?
128.6m
153.2m
167.8m
187.9m
Correct answer is B
cos 40 = \(\frac{x}{200}\)
x - 200 x cosx
= 200 x 0.7660
x = 153.2m
122o
184o
190o
226o
Correct answer is B
No explanation has been provided for this answer.
Divide the sum of 8, 6, 7, 2, 0, 4, 7, 2, 3, by their mean
9
8
7
6
Correct answer is A
Sum = 8 + 6 + 7 + 2 + 0 + 4 + 7 + 2 + 3 = 39
mean = \(\frac{39}{9}\) = 4.33
then \(\frac{sum}{mean}\) = \(\frac{39}{4.33}\)
= 9