The table shows the ages(in years) of twenty children chosen at random from a community. What is the median of the distribution? \(\begin{array}{c|c} Age(years) & 1 & 2 & 3 & 4 & 5 \\ \hline {\text {Number of children}} & 2 & 3 & 5 & 6 & 4 \end{array}\)

A.

3.5 years

B.

3.0 years

C.

2.5 years

D.

2.0 years

Correct answer is A

Median = (\(\frac{n + 1}{2})^{th}\)

= \(\frac{20 + 1}{2} = \frac{21}{2}\)

= 10.5

= \(\frac{{\text{10th term and 11th term}}}{2}\)

= \(\frac{3 + 4}{2} = \frac{7}{2}\)

= 3.5yrs