The sum of the interior angles of regular polygon is 1800o. How many sides has the polygon?
16
12
10
8
Correct answer is B
Sum = (n - 2)180
1800 = (n - 2)180
divide both sides by 180o
\(\frac{1800}{180}\) = (n - 2)\(\frac{180}{180}\)
10 = n - 2
10 + 2 = n
n = 12
Solve (\(\frac{27}{125}\))-\(\frac{1}{3}\) x (\(\frac{4}{9}\))\(\frac{1}{2}\)
\(\frac{10}{9}\)
\(\frac{9}{10}\)
\(\frac{2}{5}\)
\(\frac{12}{125}\)
Correct answer is A
(\(\frac{27}{125}\))-\(\frac{1}{3}\) x (\(\frac{4}{9}\))\(\frac{1}{2}\)
= (\(\frac{3^3}{5^3}\))-\(\frac{1}{3}\)-\(\frac{1}{3}\) x (\(\frac{3^2}{3^2}\))\(\frac{1}{2}\) -\(\frac{1}{2}\)
= \(\frac{3^{-1}}{3^{-1}} \times \frac{2}{3}\)
= \(\frac{\frac{1}{3}}{\frac{1}{5}} \times \frac{2}{3}\)
\(\frac{1}{3} \times \frac{5}{1} \times {2}{3} = \frac{10}{9}\)
N43,200.00
N43,000.00
N42,200.00
N40,000.00
Correct answer is A
let the total amount be Nx i.e (\(\frac{1}{4}\))x + (\(\frac{1}{3}\))x + 72,000 = x
\(\frac{x}{4} + \frac{x}{4} + 72,000 = x\)
\(\frac{3x + 4x + 86,400}{12} = x\)
cross multiply to clear fraction
12x = 3x + 4x + 86,400
12x - 7x = 86,400
5x = 86,400
x - \(\frac{86,400}{5}\) = 172,800
amount spent on food = \(\frac{1}{4} \times 172,800\)
= N43,200
If p = {prime factors of 210} and Q = {prime less than 10}, find p \(\cap\) Q
{1,2, 3}
{2, 3, 5}
{1, 3, 5,7}
{2,3,5,7}
Correct answer is D
prime factor of 210 = 2, 3, 5, 7
prime numbers less than 10 = 2, 3, 5 , 7
Express 3 - [\(\frac{x - y}{y}\)] as a single fraction
\(\frac{3xy}{y}\)
\(\frac{x - 4y}{y}\)
\(\frac{4y - x}{y}\)
3 - \(\frac{x - y}{y}\)
Correct answer is C
(\(\frac{x -y}{y}\)); \(\frac{3}{1} - \frac{x y}{y}\)
= \(\frac{3y - (x - y)}{y}\)
= \(\frac{3y - x + y}{y}\)
= \(\frac{4y - x}{y}\)