13
11
5
9
Correct answer is B
Using the venn diagram above
μ = 30
n(W) = 15
n(M) = 13
\(n(W ∪ M)^1 = 6\)
Let x = number of students that study both woodwork and metalwork
i.e. n(W ∩ M) = x
Number of students that study only woodwork,\(n(W ∩ M^1)\) = \(15 - x\)
Number of students that study only metalwork, \(n(W^1 ∩ M)\) = \(13 - x \)
Bringing all together,
\(n(W ∩ M^1)\) +\( n(W^1 ∩ M)\) + \(n(W ∩ M)\) + \(n(W ∪ M)^1\) = \(μ\)
∴ (15 - x) + (13 - x) + x + 6 = 30
⇒ 34 - x = 30
⇒ 34 - 30 = x
∴ x = 4
\(n(W ∩ M^1)\) = \(15 - 4 = 11\)
∴ The number of students that study woodwork but not metalwork is 11.
\(11.6cm^2\)
\(12.7cm^2\)
\(10.2cm^2\)
\(9.4cm^2\)
Correct answer is A
\(\theta = 115° , radius = 3.4cm^2\)
Area of a sector = \(\frac{\theta}{360} \times \pi r^2\)
= \(\frac{115}{360} \times \frac{22}{7} \times 3.4\times 3.4\)
= \(\frac{29246.4}{2520}\)
= \(11.6cm^2\)
15.44%
15.43%
15.42%
15.45%
Correct answer is D
Original population = 1,230
New population = 1,040
Decrease in population = 1,230 – 1,040 = 190
Percentage decrease in population = decrease in population x 100%
original population
= \(\frac {190}{1,230}\) x 100 = 15.45%
-49
64
113
15
Correct answer is D
Given that, a * b = a\(^2\)b and a ^ b = 2a + b
(-4 * 2) = (-4)\(^2\) x 2 = 16 x 2 = 32
(7 * -1) = 7\(^2\) x (-1) = 49 x (-1) = -49
∴ (-4 * 2) ^ (7 * -1) = 2(32) + (-49) = 64 - 49 = 15
How many different 8 letter words are possible using the letters of the word SYLLABUS?
(8 - 1)!
\(\frac{8!}{2!}\)
\(\frac{8!}{2! 2!}\)
8!
Correct answer is C
SYLLABUS has 8 letters, 2S's and 2L's
\(\frac{8!}{2! 2!}\)
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