x = 2,3
x = 0,3
x = \(\frac{1}{2}\), \(\frac{1}{3}\)
x = \(\frac{1}{2}\), \(\frac{-1}{3}\)
Correct answer is C
6x\(^2\) = 5x - 1
→ 6x\(^2\) - 5x + 1 = 0
Factorization:
factors are -3x and -2x
6x\(^2\) - 3x -2x + 1 = 0
(6x\(^2\) - 3x) (-2x + 1) = 0
3x(2x-1) -1(2x-1) = 0
(3x-1) (2x-1) = 0
x = \(\frac{1}{2}\), \(\frac{1}{3}\)
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