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JAMB Mathematics Past Questions & Answers - Page 85

421.

Solve for x and y respectively
3x - 5y = 9
6x - 4y = 12

$\frac{3}{4}$ , 1

$\frac{4}{3}$ , 1

$\frac{3}{4}$ , -1

$\frac{4}{3}$ , -1

View answer & explanation

Correct answer is D

3x - 5y = 9 ------x2
6x - 4y = 12 -----x1
6x - 10y = 18
-6x - 4y = 12
____________
$\frac{6y}{-6}$ = $\frac{6}{6}$

y = -1
in eq (1) 3x - 5y = 9
3x - 5(-1) = 9
3x + 5 = 9
3x = 4
x = $\frac{4}{3}$

422.

If N = $\frac{p}{2}$ ( $\frac{T_1 - T_2}{T_1}$ ). Find P when N = 12, T₁ = 27 and T₂ = 24.

108

216

View answer & explanation

Correct answer is D

N = $\frac{p}{2}$ ( $\frac{T_1 - T_2}{T_1}$ )
12 = $\frac{p}{2}$ ( $\frac{27 - 24}{27}$ )
24 = P( $frac{3}{27}$
P = 24 x 9 = 216

423.

Evaluate $\int$ (sinx - 5x²)dx

-cosx - 10x + k

cosx - $\frac{5x^3}{3}$ + k

-cosx - $\frac{5x^3}{3}$ + k

cosx - 10x + k

View answer & explanation

Correct answer is C

$\int$ ^{(sin x - 5x^2)} = -cosx - $\frac{5x^3}{3}$ + k

424.

Find $\frac{dy}{dx}$ . If y = 3x³ + 2x² + 3x + 1

9x² + 4x + 3

9x² - 4x - 3

9x² + 4x - 3

9x² - 4x + 3

View answer & explanation

Correct answer is A

y = 3x³ + 2x² + 3x + 1
$\frac{dy}{dx}$ = 9x² + 4x + 3

425.

If a car travels 120km on 45 litres of petrol, how much petrol is needed for a journey of 600km?

720 litres

160 litres

225 litres

960 litres

View answer & explanation

Correct answer is C

120km $\to$ 45litres
1km $\to$ $\frac{45}{120}$ litres
600km $\to$ $\frac{45}{120}$ x 600 = 225litres

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