Solve for x and y respectively
3x - 5y = 9
6x - 4y = 12
\(\frac{3}{4}\), 1
\(\frac{4}{3}\), 1
\(\frac{3}{4}\), -1
\(\frac{4}{3}\), -1
Correct answer is D
3x - 5y = 9 ------x2
6x - 4y = 12 -----x1
6x - 10y = 18
-6x - 4y = 12
____________
\(\frac{6y}{-6}\) = \(\frac{6}{6}\)
y = -1
in eq (1) 3x - 5y = 9
3x - 5(-1) = 9
3x + 5 = 9
3x = 4
x = \(\frac{4}{3}\)