JAMB Chemistry Past Questions & Answers - Page 66

326.

Diamond is a bad conductor of electricity because its bonding electrons are used in

A.

crystal lattice formation

B.

covalent bond formation

C.

metallic bond formation

D.

coordinate bond formation

Correct answer is B

Diamond is a covalent macromolecule, and typical of a covalent substance is an insulator. All valence electrons are localized in well-defined covalent bonds and hence are not free to move through the structure

327.

To what volume must 300cm\(^3\) of 0.60M sodium hydroxide solution be diluted to give a 0.40M solution?

A.

450cm\(^3\)

B.

300cm\(^3\)

C.

200cm\(^3\)

D.

150cm\(^3\)

Correct answer is A

From the dilution law

  C\(_1\)V\(_1\) = C\(_2\)V\(_2\)

  C\(_1\) = Initial Concentration of NaOH = 0.6M

  V\(_1\) = Initial Volume of NaOH = 300cm3

  C\(_2\) = Final Concentration of NaOH = 0.4M

  V\(_2\) = Final Volume of NaOH = ?

  V\(_2\) = \(\frac{C_1V_1}{C_2}\)

  V\(_2\) = \(\frac{0.6 \times 300}{0.4}\)

  V\(_2\) = 450 cm\(^3\)

Correct Computation as it follows the equation specified

328.

In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid?

A.

5cm\(^3\)

B.

10cm\(^3\)

C.

20cm\(^3\)

D.

50cm\(^3\)

Correct answer is D

2NaOH + H\(_2\) SO\(_4\)↔Na\(_2\)SO\(_4\) + 2H\(_2\)O

  V x 0.5M = 2(10 x 1.25)

  0.5V = 2 x 12.5

  0.5V = 25

  V = 250.5 = 50cm\(^2\)

Correct computation as it follows the equation specified.

329.

Which of the following is used to power steam engines?

A.

lubricating oil

B.

coal

C.

bitumen

D.

diesel oil

Correct answer is B

When we burn coal on a fire, the bonds break apart and the energy is released in the form of heat. Coal contains about half as much energy per kilogram as cleaner fossil fuels such as gasoline, diesel, and kerosene—and that's one reason why steam engines have to burn so much of it.

Coal is the fuel used to power steam engines.

330.

2KClO\(_3\)(s) → 2KCl(s) + 3O\(_2\)(g)
The importance of the catalyst in the reaction above is that

A.

heating may not be required before the reaction takes place

B.

the reaction is controllable even at a high temperature

C.

the reaction produces large quantity of oxygen

D.

the reaction takes place more rapidly at a lower temperature

Correct answer is D

A catalyst is a substance that enables a chemical reaction to proceed at a usually faster rate or under different conditions (as at a lower temperature) than otherwise possible.