JAMB Mathematics Past Questions & Answers - Page 56

276.

If given two points A(3, 12) and B(5, 22) on a x-y plane. Find the equation of the straight line with intercept at 2.

A.

y = 5x + 2

B.

y = 5x + 3

C.

y = 12x + 2

D.

y = 22x + 3

Correct answer is A

The equation of a straight line is given as \(y = mx + b\) 

where m = the slope of the line

b = intercept

Given points A(3, 12) and B(5, 22), the slope = \(\frac{22 - 12}{5 - 3}\)

= \(\frac{10}{2}\) = 5

Hence, the equation of the line is \(y = 5x + 2\).

278.

In the figure above, |CD| is the base of the triangle CDE. Find the area of the figure to the nearest whole number.

A.

56 cm\(^2\)

B.

24 cm\(^2\)

C.

42 cm\(^2\)

D.

34 cm\(^2\)

Correct answer is D

Area of rectangle ABCD = length x breadth

= 7 x 4 

= 28 cm\(^2\)

Area of triangle CDE = \(\frac{1}{2}\) base x height

= \(\frac{1}{2} \times 3 \times 4\)

= 6 cm\(^2\)

Area of the figure = 28 cm\(^2\) + 6 cm\(^2\)

= 34 cm\(^2\)

279.

If \(4\sin^2 x - 3 = 0\), find the value of x, when 0° \(\leq\) x \(\leq\) 90°

A.

90°

B.

45°

C.

60°

D.

30°

Correct answer is C

\(4\sin^2 x - 3 = 0\)

\(4 \sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}\)

\(\sin x = \frac{\sqrt{3}}{2}\)

\(\therefore x = \sin^{-1} (\frac{\sqrt{3}}{2})\)

x = 60°

280.

From the cyclic quadrilateral MNOP above, find the value of x.

A.

16°

B.

25°

C.

42°

D.

39°

Correct answer is D

The sum of two opposite angles of a cyclic quadrilateral = 180°

\(\therefore\) (2x + 18)° + 84° = 180°

2x + 102° = 180° \(\implies\) 2x = 78°

x = 39°