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JAMB Mathematics Past Questions & Answers - Page 4

16.

Find the value of x in the diagram above

A.

10 units

B.

15 units

C.

5 units

D.

20 units

Correct answer is A

Intersecting Chords Theorem states that If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.

⇒ AE * EB = CE * ED

⇒ 6 * x = 4 * (x + 5)

⇒ 6x = 4x + 20

⇒ 6x - 4x = 20

⇒ 2x = 20

x=202 = 10 units

17.

Calculate the area of the composite figure above.

A.

6048 m2

B.

3969 m2

C.

4628 m2

D.

5834 m2

Correct answer is B

Area of the composite figure = Area of semi circle + Area of rectangle + Area of triangle

Area of semi circle = 12πr2=12×π×d24=12×227×4224=693m2

Area of rectangle = l x b = 42 x 60  =2520 m2

Area of triangle = 12×b×h=12×36×42=756m2

∴ Area of the composite figure = 693 + 2520 + 756 = 3969 m2

18.

Solve the logarithmic equation: log2(6x)=3log2x

A.

x = 4 or 2

B.

x = -4 or -2

C.

x = -4 or 2

D.

x = 4 or -2

Correct answer is A

log2(6x)=3log2x

log2(6x)=3log22log2x (since log2 2 = 1)

log2(6x)=log223log2x (alog c = log ca)

log2(6x)=log28log2x

log2(6x)=log28x (log a - log b = logab)

6x=8x

x(6x)=8

6xx2=8

x26x+8=0

x24x2x+8=0

x(x4)2(x4)=0

(x4)(x2)=0

x4=0orx2=0

∴ x = 4 or 2

19.

Tickets for the school play were priced at ₦520.00 each for adults and ₦250.00 each for kids. How many kids' tickets were sold if the total sales were ₦171,000.00 and there were 5 times as many adult tickets sold as children's tickets?

A.

20

B.

300

C.

50

D.

60

Correct answer is D

Let number of children's ticket at ₦250.00 each = x

∴ Number of adult tickets at ₦520.00 each = 5x

Then,

Total amount of money received from children's tickets = 250x

Total amount of money received from adult tickets = 520(5x)

⇒ 250x + 520(5x) = 171,000

⇒ 250x + 2600x = 171,000

⇒ 2850x = 171,000

x=171,0002850=60

∴ 60 tickets were sold at ₦250.00 and 300 tickets were sold at ₦520.00

20.

The line 3y+6x = 48 passes through the points A(-2, k) and B(4, 8). Find the value of k.

A.

16

B.

20

C.

8

D.

-2

Correct answer is B

The line: 3y+6x = 48

Divide through by 3

⇒ y + 2x = 16

⇒ y = -2x + 16

∴ The gradient of the line = -2

The points: A(-2, k) and B (4, 8)

m =y2y1x2x1=8k4(2)

⇒ m =\frac[8 - k}{4 + 2} = {8 - k}{6}

Since the line passes through the points

∴ -2 = 8k6

\frac{-2}[1} = \frac{8 - k]{6}

⇒ 8 - k = -12

⇒ k = 8 + 12

∴ k = 20