Find the standard deviation of 2,3,8,10 and 12
3.9
4.9
5.9
6.9
Correct answer is A
\(\begin{array}{c|c} x & (x - \varkappa) & (x - \varkappa)^2 \\ \hline 2 & -5 & 25 \\ \hline 3 & -4 & 16 \\ \hline 8 & 1 & 1 \\ \hline 10 & 3 & 9 \\ \hline 12 & 5 & 25 \\ \hline & & 76
\end{array}\)
S.D = \(\sqrt{\frac{(x - \varkappa)^2}{n}}\)
S.D = \(\sqrt{\frac{76}{5}}\)
S.D = 3.9
Find the range of 4,9,6,3,2,8,10 and 11
11
9
8
4
Correct answer is B
Range = Highest Number - Lowest Number
Range = 11 - 2 = 9
Find the median of 2,3,7,3,4,5,8,9,9,4,5,3,4,2,4 and 5
9
8
7
4
Correct answer is D
Arrange all the values in ascending order, 2,2,3,3,3,4,4,4,4,5,5,5,7,8,9,9
126
180
216
224
Correct answer is D
\(\frac{x}{7} = \frac{96}{1}\) ==> \(\frac{672 + x}{8} = 112\)
Therefore x = 224
Evaluate \(\int^{\frac{\pi}{4}}_0sec^2 \theta d \theta\)
1
2
3
4
Correct answer is A
\(\int^{\frac{\pi}{4}}_0sec^2 \theta d \theta\)
= \([\tan \theta]_{0} ^{\frac{\pi}{4}}\)
= \(\tan \frac{\pi}{4} - \tan 0\)
= \(1 - 0\)
= 1.