\(\frac{1}{3}\)
\(\frac{1}{9}\)
\(\frac{1}{27}\)
\(\frac{1}{81}\)
Correct answer is D
log3x2 = -8 x2 = 3-8 x = \(3^{-8 \times \frac{1}{2}}\) x = 3-4 x = \(\frac{1}{3^4}\) x = \(\frac{1}{81}\)
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