JAMB Physics Past Questions & Answers - Page 30

146.

Which of the following instruments may be used to measure relative humidity?

A.

Hydrometer

B.

Manometer

C.

Hygrometer

D.

Hypsometer

Correct answer is C

A hygrometer is an instrument that is used to measure water vapor in the atmosphere. This is also commonly referred to as relative humidity in the atmosphere.

147.

0.5kg of water at 10ºC is completely converted to ice at 0ºC by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg\(^{1}\) Cº. Calculate the specific latent heat of fusion of ice.

A.

9.0kjkg\(^{-1}\)

B.

84.0kjkg\(^{-1}\)

C.

134.0kjkg\(^{-1}\)

D.

168.0kjkg\(^{-1}\)

Correct answer is C

Heat involved (H) = 88,000J, Mass(M)= 0.5kg,  specific heat capacity of water(C) = 4200JkgºC,

Specific latent heat of fusion(L) = ?, Temperature change(Δθ) =  θ2 -  θ1 =  (10 - 0)° = 10°

H = MCΔθ + ML 

or

H = M(CΔθ + L) -->\(\frac{H}{M}\) = CΔθ + L 

: L = \(\frac{H}{M}\) -  CΔθ = \(\frac{88,000}{0.5}\) - 4200 \(\times\) 10

L = 176,000 - 42000 = 134,000

L = 134,000 or 134kj/kg

 

148.

A given mass of gas has a pressure of 80 Nm\(^{-2}\) at a temperature of 47 C. If the temperature is reduced to 27 C with volume remaining constant, the new pressure is?

A.

46.0 Nm\(^{-2}\)

B.

75.0 Nm\(^{-2}\)

C.

80.0 Nm\(^{-2}\)

D.

85.3 Nm\(^{-2}\)

Correct answer is B

Using \(\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\)

P\(_{1}\) = 80Nm\(^{2}\)
T\(_{1}\) = 47 + 273 = 320k
T\(_{2}\) = 27 + 273 = 300k
P\(_{2}\)?

\(\therefore\) = P\(_{2}\) = \(\frac{P_{1}T_{2}}{T_{1}}\)

= \(\frac{80 \times 300}{320}\) = 75.Nm\(^{2}\)

149.

In which of the following media is the speed of sound the least?

A.

Air

B.

Brass

C.

Water

D.

Wood

Correct answer is A

No explanation has been provided for this answer.

150.

A transverse pulse of frequency 9 Hz traves 4.5m in 0.6 s. Calculate the wavelength of the pulse.

A.

3.33 m

B.

0.30 m

C.

0.83 m

D.

1.20 m

Correct answer is C

Wavelength (\(\alpha\)) = \(\frac{Velocity (V)}{Frequency (f)}\)

Velocity = \(\frac{Distance}{Time}\) = \(\frac{4.5}{0.6}\)

= \(\frac{7.5}{9.0}\)

= 0.83m