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JAMB Mathematics Past Questions & Answers - Page 30

146.

Simplify and express in standard form $\frac{0.00275 \times 0.00640}{0.025 \times 0.08}$

A.

8.8 x 10^-1

B.

8.8 x 10^-2

C.

8.8 x 10^-3

D.

8.8 x 10³

View answer & explanation

Correct answer is C

$\frac{0.00275 \times 0.0064}{0.025 \times 0.08}$

Removing the decimals = $\frac{275 \times 64}{2500 \times 800}$

= $\frac{88}{10^4}$

88 x 10-4 = 88 x 10-1 x 10-4

= 8.8 x 10-3

147.

At what rate would a sum of N100.00 deposited for 5 years raise an interest of N7.50?

A.

$\frac{1}{2}$ %

B.

2 $\frac{1}{2}$ %

C.

1.5%

D.

25%

View answer & explanation

Correct answer is C

Interest I = $\frac{PRT}{100}$

∴ R = $\frac{100 \times 1}{100 \times 5}$

= $\frac{100 \times 7.50}{500 \times 5}$

= $\frac{750}{500}$

= $\frac{3}{2}$

= 1.5%

148.

Correct 241.34(3 x 10 $^{-3}$ ) $^2$ to 4 significant figures

A.

0.0014

B.

0.001448

C.

0.0022

D.

0.002172

View answer & explanation

Correct answer is D

first work out the expression and then correct the answer to 4 s.f = 241.34..............(A)

(3 x 10- $^3$ ) $^2$ ............(B)

= 3 $^2$ x $^2$

= $\frac{1}{10^3}$ x $\frac{1}{10^3}$

(Note that x $^2$ = $\frac{1}{x^3}$ )

= 24.34 x 3 $^2$ x $\frac{1}{10^6}$

= $\frac{2172.06}{10^6}$

= 0.00217206

= 0.002172(4 s.f)

149.

Find the derivative of the function y = 2x $^2$ (2x - 1) at the point x = -1?

A.

18

B.

16

C.

-4

D.

-6

View answer & explanation

Correct answer is B

y = 2x $^2$ (2x - 1)
y = 4x $^3$ - 2x $^2$
dy/dx = 12x $^2$ - 4x
at x = -1
dy/dx = 12(-1) $^2$ - 4(-1)
= 12 + 4
= 16

150.

Find the value of p if the line which passes through (-1, -p) and (-2,2) is parallel to the line 2y+8x-17=0?

A.

$\frac{-2}{7}$

B.

$\frac{7}{6}$

C.

$\frac{-6}{7}$

D.

2

View answer & explanation

Correct answer is D

Line: 2y+8x-17=0

recall y = mx + c

2y = -8x + 17

y = -4x + $\frac{17}{2}$

Slope m $_1$ = 4

parallel lines: m $_1$ . m $_2$ = -4

where Slope ( -4) = $\frac{y_2 - y_1}{x_2 - x_1}$ at points (-1, -p) and (-2,2)

-4( $x_2 - x_1$ ) = $y_2 - y_1$

-4 ( -2 - -1) = 2 - -p

p = 4 - 2 = 2

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