\(\frac{2}{3}\)
\(\frac{1}{2}\)
\(\frac{1}{3}\)
\(\frac{1}{4}\)
Correct answer is B
\(\begin{array}{c|c} 1 & 2 & 3 & 4\\\hline 1(1, 1) & (1, 2) & (1, 3) & (1, 4)\\ \hline 2(2, 1) & (2 , 2) & (2, 3) & (2, 4) \\ \hline 3(3, 1) & (3, 2) & (3, 3) & (3, 4)\\ \hline 4(4, 1) & (4, 2) & (4, 3) & (4, 4)\end{array}\)
sample space = 16
sum of nos. removed are (2), 3, (4), 5
3, (4), 5, (6)
(4), 5, (6), 7
(5), 6, 7, (8)
Even nos. = 8 of them
Pr(even sum) = \(\frac{8}{16}\)
= \(\frac{1}{2}\)
3
16
38
30
Correct answer is C
Mean of 10 numbers = 16
The total sum of numbers = 16 x 10 = 160
Mean of 11 numbers = 18
Total sum of numbers = 11 x 18
= 198
The 11th no. = 198 - 160
= 38
48o
84o
92o
276o
Correct answer is D
Given that 4, 16, 30, 20, 10, 14 and 26
Adding up = 120
nos \(\geq\) 16 are 16 + 30 + 20 + 26 = 92
The requires sum of angles = \(\frac{92}{120}\) x \(\frac{360^o}{1}\)
= 276o
perpendicular bisector of the two lines
angle bisector of the two lines
bisector of the two lines
line parallel to the two lines
Correct answer is B
The required locus is angle bisector of the two lines
153\(\pi\)cm3
207\(\pi\)cm3
15 300\(\pi\)cm3
20 700\(\pi\)cm3
Correct answer is D
Volume of a cylinder = πr\(^2\)h
First convert 3m to cm by multiplying by 100
Volume of External cylinder = \(π \times 13^2 \times 300\)
Volume of Internal cylinder = \(π \times 10^2 \times 300\)
Hence; Volume of External cylinder - Volume of Internal cylinder
Total volume (v) = \(π (169 - 100) \times 300\)
V = \(π \times 69 \times 300\)
V = 20700πcm\(^3\)