x = \(\frac{3}{2}\), y = \(\frac{3}{2}\)
x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
x = \(\frac{-1}{2}\), y = \(\frac{-3}{2}\)
x = \(\frac{1}{3}\), y = \(\frac{3}{2}\)
Correct answer is B
\(\frac{2}{x} - {\frac{3}{y}}\) = 2.....(1)
\(\frac{4}{x} + {\frac{3}{y}}\) = 10 ... (2)
(1) + (2):
\(\frac{6}{x}\) = 12 \(\to\) x = \(\frac{6}{12}\)
x = \(\frac{1}{2}\)
put x = \(\frac{1}{2}\) in equation (i)
= 4 - \(\frac{3}{y}\) = 2
= 4 - 2
= \(\frac{3}{y}\)
therefore y = \(\frac{3}{2}\)
If the function f(fx) = x3 + 2x2 + qx - 6 is divisible by x + 1, find q
-5
-2
2
5
Correct answer is A
x + 1 = 0, x = -1; f(x) = x3 + 2x2 + qx - 6
0 = -1 + 2 - q - 6
q = -5
0
9
11
20
Correct answer is B
Let the number of students that speak Hausa and Igbo be represented by H and I respectively.
n(H only) = 80 - 9 = 71.
n(I only) = 20 - 9 = 11.
n(neither H nor I) = 100 - (71 + 9 + 11)
= 100 - 91 = 9 students.
(p, o, u, r)
(s, p, d, r)
(s, p, n, e)
(n, d, u)
Correct answer is C
\(Y \cup Z\) = \({s, e, n, o, u, p, r}\)
\(X \cap (Y \cup Z)\) = \({p, e, n}\)
Find the simple interest rate percent per annum at which N1,000 accumulates to N1,240 in 3 years
6%
8%
10%
12%
Correct answer is B
1 = \(\frac{PRT}{100}\)
1 = 1240 - 1000
= 240
R = \(\frac{240 \times 100}{100 \times 3}\)%
= 8%