A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.
r16 cm
r6 cm
r8 cm
r2 cm
Correct answer is C
The formula for the base radius of a cone formed from the sector of a circle = \frac{r \theta}{360°}
= \frac{r \times 45°}{360°}
= \frac{r}{8} cm