The 4th term of an A.P. is 13 while the 10th term is 31. Find the 21st term.
175
85
64
45
Correct answer is C
a + 3d = 13
a + 9d = 31
6d = 18
= d = 3
a = 13 - 9
= 4
a + 20d = 4 + (20 x 3)
= 64
Solve the inequality (x - 3)(x - 4) \(\leq\) 0
3 \(\leq\) x \(\leq\) 4
3 < x < 4
3 \(\leq\) x < 4
3 < x \(\leq\) 4
Correct answer is A
(x - 3)(x - 4) \(\leq\) 0
Case 1 (+, -) = x - 3 \(\geq\) 0, X - 4 \(\geq\) 0
= X \(\leq\) 3, x \(\geq\) 4
= 3 < x \(\geq\) 4 (solution)
Case 2 = (-, +) = x - 3 \(\leq\) 0, x - 4 \(\geq\) 0
= x \(\leq\) 3, x \(\geq\) 4
therefore = 3 \(\leq\) x \(\leq\) 4
Factorize completely the expression \(abx^2 + 6y - 3ax - 2byx\)
(ax - 2y)(bx - 3)
(bx + 3)(2y - ax)
(bx + 3)(ax - 2y)
(ax - 2y)(ax - b)
Correct answer is A
\(abx^{2} + 6y - 3ax - 2byx\)
Collecting like terms, we have
\(abx^{2} - 3ax + 6y - 2byx\)
= \(ax(bx - 3) + 2y(3 - bx)\)
= \(ax(bx - 3) - 2y(bx - 3)\)
= \((ax - 2y)(bx - 3)\)
The graph of f(x) = x2 - 5x + 6 crosses the x-axis at the points
(-6, 0), (-1, 0)
(-3, 0), (-2,0)
(-6, 0),(1, 0)
(2, 0), (3, 0)
Correct answer is D
When X = 3, Y = 0(3, 0),
When x = 2, y = 0(2, 0)
1
2
3
4
Correct answer is B
x - p,x = p
2p2 - p2 + p = 6
= p2 + p - 6
= 0
p = 3, 2