An arc of a circle subtends an angle 70° at the centre. If the radius of the circle is 6cm, calculate the area of the sector subtended by the given angle.(\(\pi\) = \(\frac{22}{7}\))
22cm2
44cm2
66cm2
88cm2
Correct answer is A
Area of a sector = \(\frac{\theta}{360°} \times \pi r^{2}\)
r = 6cm; \(\theta\) = 70°.
Area of the sector = \(\frac{70}{360} \times \frac{22}{7} \times 6^{2}\)
= \(22 cm^{2}\)