JAMB Mathematics Past Questions & Answers - Page 27

131.

A group of market women sell at least one of yam, plantain and maize. 12 of them sell maize, 10 sell yam and 14 sell plantain. 5 sell plantain and maize, 4 sell yam and maize, 2 sell yam and plantain only while 3 sell all the three items. How many women are in the group?

A.

25

B.

19

C.

18

D.

17

Correct answer is A

Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.

132.

X is due east point of y on a coast. Z is another point on the coast but 6.0km due south of Y. If the distance ZX is 12km, calculate the bearing of Z from X

A.

240°

B.

150°

C.

60°

D.

270°

Correct answer is A

Sinθ = \(\frac{6}{12}\)

Sinθ = \(\frac{1}{2}\)

θ =  Sin\(^0.5\)
θ = 30°

Bearing of Z from X, (270 - 30)° = 240°

133.

List all integers satisfying the inequality in -2 < 2x-6 < 4 

A.

2,3,4 and 5

B.

2,3

C.

2,5

D.

3,4

Correct answer is D

-2 < 2x - 6 AND 2x - 6 < 4 -2 + 6 <2x AND 2x < 4 + 6 4 <2x AND 2x < 10 : 2

134.

Find x if log\(_9\)x = 1.5

A.

27

B.

15

C.

3.5

D.

32

Correct answer is A

If log\(_9\)x = 1.5,

9\(^{1.5}\) = x

9^\(\frac{3}{2}\) = x

(√9)\(^3\) = 3

∴ x = 27

135.

Factorize completely 81a\(^4\) - 16b\(^4\)

A.

(3a + 2b)(2a - 3b)(9a2 + 4b2)

B.

(3a - 2b)(2a - 3b)(4a2 - 9b2)

C.

(3a - 2b)(3a + 2b)(9a2 + 4b2)

D.

(6a - 2b)(8a - 3b)(4a3 - 9b2)

Correct answer is C

81a\(^4\) - 16b\(^4\) = (9a\(^2\))\(^2\) - (4b\(^2\))\(^2\)

= (9a\(^2\) + 4b\(^2\))(9a\(^2\) - 4b\(^2\))

N:B 9a\(^2\) - 4b\(^2\) = (3a - 2b)(3a + 2b)