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JAMB Mathematics Past Questions & Answers - Page 27

131.

A group of market women sell at least one of yam, plantain and maize. 12 of them sell maize, 10 sell yam and 14 sell plantain. 5 sell plantain and maize, 4 sell yam and maize, 2 sell yam and plantain only while 3 sell all the three items. How many women are in the group?

A.

25

B.

19

C.

18

D.

17

Correct answer is A

Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.

132.

X is due east point of y on a coast. Z is another point on the coast but 6.0km due south of Y. If the distance ZX is 12km, calculate the bearing of Z from X

A.

240°

B.

150°

C.

60°

D.

270°

Correct answer is A

Sinθ = 612

Sinθ = 12

θ =  Sin0.5
θ = 30°

Bearing of Z from X, (270 - 30)° = 240°

133.

List all integers satisfying the inequality in -2 < 2x-6 < 4 

A.

2,3,4 and 5

B.

2,3

C.

2,5

D.

3,4

Correct answer is D

-2 < 2x - 6 AND 2x - 6 < 4 -2 + 6 <2x AND 2x < 4 + 6 4 <2x AND 2x < 10 : 2

134.

What is the n-th term of the sequence 2, 6, 12, 20...?

A.

4n - 2

B.

2(3n - 1)

C.

n2 + n

D.

n2 + 3n + 2

Correct answer is C

Given that 2, 6, 12, 20...? the nth term = n2 + n

check: n = 1, u1 = 2

n = 2, u2 = 4 + 2 = 6

n = 3, u3 = 9 + 3 = 12

∴ n = 4, u4 = 16 + 4 = 20

135.

The angles of a quadrilateral are 5x-30, 4x+60, 60-x and 3x+61.find the smallest of these angles​

A.

5x - 30

B.

4x + 60

C.

60 - x

D.

3x + 61

Correct answer is C

Sum of all 4 angles of a quadrilateral = 360°

(5x-30) + (3x + 61) + (60-x) + (4x+ 60) = 360°

11x + 151 = 360°

11x = 360 - 151 = 209

x = 209/11 = 19°

Each angles is :

5x - 30 =  65°

4x+ 60 = 136°

60 - x =41°

3x + 61 = 118°

 

Smallest of these angles is 41°