X is due east point of y on a coast. Z is another point on the coast but 6.0km due south of Y. If the distance ZX is 12km, calculate the bearing of Z from X
A.
240°
B.
150°
C.
60°
D.
270°
Correct answer is A
Sinθ = \(\frac{6}{12}\)
Sinθ = \(\frac{1}{2}\)
θ = Sin\(^0.5\)
θ = 30°
Bearing of Z from X, (270 - 30)° = 240°