i and ii only
ii and iii only
i and iii only
i, ii, and iii only
Correct answer is A
No explanation has been provided for this answer.
30cm and virtual
6cm and real
6cm and virtual
30cm and real
Correct answer is A
F = \(\frac{uv}{u + v}\)
15 = \(\frac{10 \times v}{10 + v}\)
v = -30cm
0.13m
0.25m
0.28m
0.50m
Correct answer is C
v = 2.5u
F = \(\frac {uv}{u + v}\)
0.2 = \(\frac {u \times 2.5u}{u + 2.5u}\)
u = 0.28m
2 : 1
1 : 2
1 : 4
1 : 16
Correct answer is D
F = \(\frac{1}{2L}\)\(\sqrt\frac{T}{m}\)
\(\frac{F_1}{F_2}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\frac{1}{4}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\frac{m_2}{m_1}\) = \(\frac{1}{16}\)
A slight loading of a tuning fork has the effect of
decreasing its amplitude
increasing its amplitude
decreasing its frequency
increasing its frequency
Correct answer is C
When the prongs of the tuning fork are loaded, it causes an increase in their inertia, thereby decreasing the frequency of the fork.