Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.

A.

0.20V

B.

0.86V

C.

1.71V

D.

3.43V

View answer & explanation

Correct answer is B

Using voltage - divider method

v1 = \(\frac{(R_1)}{R_T}\)VT

= \(\frac{250}{1750}\) x \(\frac{6}{1}\)

= 0.86V

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