4.0 x 102kgm-3
4.0 x 103kgm-3
1.0 x 103kgm-3
1.0 x 106kgm-3
Correct answer is B
since the object floats, density of liquid = density of object
converting 500cm3 to m3,
\(\frac{500}{10^{6}} = 5 \times 10^{-4}m^{3}\)
D = \(\frac{m}{v}\)
= \(\frac{2}{5 \times 10^{-4}}\)
=\(4.0 \times 10^{3}kgm^{-3}\)
0.02
0.08
0.20
0.80
Correct answer is B
\(\mu\)mg = ma
\(\mu\)mg = F - ma
\(\mu\) x 10 x 10 = 10 - (10 x 0.2)
100 \(\mu\) =10 - 2
dividing both sides by 100
\(\mu\) = 8 / 100
\(\mu\) = 0.08
5.3s
34.5s
41.6s
52.8s
Correct answer is D
power = mgh
0.25 x 103 = \(\frac {60 \times 10 \times 22}{t}\)
t = 52.8 sec
3 rev s-1
40 rev s-1
360 rev s-1
2400 rev s-1
Correct answer is C
\(\frac{\text {speed of driver}}{\text {speeder driven}}\) = \(\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}\)
\(\frac{120}{V}\) = \(\frac{20}{60}\)
v = 360 rev s-1
2.5m
5.0m
25.0m
50.0m
Correct answer is C
X = ut + \(\frac{1}{2}\)at
= (0 x 10) + (\(\frac{1}{2}\) x 0.5 x 10 x 10)
= 25m