JAMB Mathematics Past Questions & Answers - Page 252

1,256.

Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)

The mean and the median of the distribution are respectively

A.

6.7, 6

B.

7.6, 5

C.

5.7, 87

D.

34, 6

Correct answer is A

No of defective(x) No of boxes (f) \(fx\)
4 2 8
5 7 35
6 17 102
7 10 70
8 8 64
9 6 54
\(\sum\) 50 333

\(Mean = \frac{\sum fx}{\sum f}\)

= \(\frac{333}{50} = 6.66 \approxeq 6.7\)

The median is the average of the 25th and 26th position = 6.

 

1,257.

3% of a family's income is spent on electricity, 59% on food, 20% on transport, 11% on education and 7% on extended family. The angles subtended at the centre of the pie chart under education and food are respectively

A.

76.8o and 25.2o

B.

10.8o and 224.6o

C.

112.4o and 72.0o

D.

39.6o and 212.4o

Correct answer is D

Education = 11% = \(\frac{11}{100} \times 360° = 39.6°\)

Food = 59% = \(\frac{59}{100} \times 360° = 212.4°\)

1,258.

Find the total area of the surface of a solid cylinder whose base radius is 4cm and height is 5cm

A.

56\(\pi\) cm2

B.

72\(\pi\) cm2

C.

96\(\pi\) cm2

D.

192\(\pi\) cm2

Correct answer is B

The total surface area of a cylinder = \(2\pi r (r + h)\)

= \(2 \pi (4) (4 + 5)\)

= \(8 \pi (9) = 72 \pi cm^{2}\)

1,259.

From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.

A.

0.30o

B.

045o

C.

060o

D.

090o

Correct answer is C

tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)

\(\theta\) = tan \(\frac{1}{3}\) = 60o

Bearing of y from x = 060o

1,260.

If cos x = \(\sqrt{\frac{a}{b}}\) find cosec x

A.

\(\frac{b}{\sqrt{b - a}}\)

B.

\(\sqrt{\frac{b}{a}}\)

C.

\(\sqrt{\frac{b}{b - a}}\)

D.

\(\sqrt{\frac{b - a}{a}}\)

Correct answer is C

cosx = \(\sqrt{\frac{a}{b}}\)

y2 + \(\sqrt{(a)^2}\) = \(\sqrt{(b)^2}\) by pythagoras

y2 = b - a

∴ y = b - a

cosec x = \(\frac{1}{sin x}\) = \(\frac{1}{y}\)

\(\frac{b}{y}\) = \(\frac{\sqrt{b}}{\sqrt{b - a}}\)

= \(\sqrt{\frac{b}{b - a}}\)