JAMB Mathematics Past Questions & Answers - Page 240

1,196.

Factorize 4a2 - 12ab - C2 + 9b2

A.

4a(a - 3b) + (3b - c)2

B.

(2a + 3b - c)(2a + 3b + c)

C.

(2a - 3b + c)(2a - 3b - c)

D.

4a(a - 3b) + (3b + c)

Correct answer is C

4a2 - 12ab - C2 + 9b2

rearranges: (4a2 - 12ab + 9b2) - c2

(2a - 3b)(2a - 3b) - c2 = (2a - 3b)2 - c2

= (2a - 3b + c)(2a - 3b - c)

1,197.

Factorize completely \(y^3 -4xy + xy^3 - 4y\)

A.

(y + xy)(y + 2)(y - 2)

B.

(y - xy)(y - 2)

C.

y(1 + x)(y + 2)(y -2)

D.

y(1 - x)(y + 2)(y - 2)

Correct answer is C

\(y^3 -4xy + xy^3 - 4y \)

= \(y^3(1 + x) - 4y(1 + x)

\((y^3 - 4y)(1 + x) = (y^3(1 + x) - 4y(1 + x))\)

∴ = \(y(1 + x)(y + 2)(y - 2)\)

1,198.

Simplify \(\frac{324 - 4x^2}{2x + 18}\)

A.

2(x - 9)

B.

2(9 + x)

C.

81 - x2

D.

-2(x - 9)

Correct answer is D

\(\frac{324 - 4x^2}{2x + 18}\) = \(\frac{18^2 - (2x)^2}{2x + 18}\)

= \(\frac{(18 - 2x)(18 + 2x)}{(2x + 18)}\)

18 - 2x = 2(9 - x)

or -2(x - 9)

1,199.

Solve for a positive number x such that \(2^{(x^3 - x^2 - 2x)} = 1\)

A.

4

B.

3

C.

2

D.

1

Correct answer is C

\(2^{(x^3 - x^2 - 2x)} = 1\)

\(x^3 - x^2 - 2x = 0\)

\(x(x^2 - x - 2) = 0\)

\(x^2 - x - 2 = 0\)

\((x + 1)(x - 2) = 0\)

x = 2 is the positive answer.

1,200.

If \(f(x) = 2x^2 - 5x + 3\), find f(x + 1).

A.

2x2 - x

B.

2x2 - x + 10

C.

4x2 + 3x + 2

D.

4x2 + 3x + 12

Correct answer is A

\(f(x) = 2x^2 - 5x + 3\)

\(f(x + 1) = 2(x + 1)^2 - 5(x + 1) + 3\)

= \(2(x^2 + 2x + 1) - 5x - 5 + 3\)

= \(2x^2 + 4x + 2 - 5x - 2\)

= \(2x^2 - x\)