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If Cos θ = 1213. Find θ + cos...

If Cos θ = 1213. Find θ + cos2θ

A.

16925

B.

25169

C.

169144

D.

144169

Correct answer is A

Cos θ = 1213

x2 + 122 = 132

x2 = 169- 144 = 25

x = 25

= 5

Hence, tanθ = 512 and cosθ = 1213

If cos2θ = 1 + 1tan2θ

= 1 + 1(5)212

= 1 + 125144

= 1 + 14425

= 25+14425

= 16925