44oC
50oC
56oC
60oC
70oC
Correct answer is C
Heat lost = heat gained
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC
1.503m2
1.500m2
1.498m2
1.497m2
1.490m2
Correct answer is C
\(\beta\) = A2 - A1
2 X 10-5 x 2.5 = \(\frac{A_2 \times 1.5}{1.5 \times (-20 -20)}\)
A2 = 1.498m2
\(\frac{1}{6}\)
\(\frac{1}{5}\)
\(\frac{1}{3}\)
\(\frac{4}{5}\)
\(\frac{5}{6}\)
Correct answer is E
Height inside H2O = \(\frac{2}{3}\)
R.d = \(\frac{\text{height inside}H_2O}{\text{height inside liquid}}\)
0.8 = \(\frac{\frac{2}{3}}{X}\)
6.67 x 100mm
8.50 x 102mm
1.15 x 103mm
2.50 x 103mm
1.50 x 105mm
Correct answer is A
Height = \(\frac{volume}{area}\)
= Height = \(\frac{10^3}{1.5 \times 10^2}\)
= 6.67mm
10N
100N
500N
1000N
5000N
Correct answer is D
\(\frac{load}{area}\) = \(\frac{effort}{area}\)
\(\frac{load}{5}\) = \(\frac{100}{0.5}\)
load = 1000N