sin-1\(\frac{1}{2}\)
sin-1\(\frac{2}{3}\)
sin-1\(\frac{3}{4}\)
sin-1\(\frac{8}{9}\)
Correct answer is B
sin ic \(\frac{1}{n}\) = \(\frac{1}{1 - 5}\) i = sin-1\(\frac{1}{1 - 5}\) = sin-1\(\frac{10}{15}\) = sin-1\(\frac{2}{3}\)
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