15
25
30
50
Correct answer is B
Let x r3epresent total number of pencils shared
B : S : T = 2 + 3 + 5 = 10
2 : 3 : 5
= \(\frac{2}{10}\) x y
= 5
2y =5
2y = 50
∴ y = \(\frac{50}{2}\)
= 25
11%
7\(\frac{1}{3}\)%
5
3\(\frac{1}{2}\)%
Correct answer is B
S.I = \(\frac{PTR}{100}\)
R = \(\frac{100}{PT}\)
\(\frac{100 \times 50}{150 \times 6}\) = \(\frac{22}{3}\)
= 7\(\frac{1}{3}\)%
Simplify \(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\)
3.6 x 102
3.6 x 10-2
3.6 x 10-3
3.6 x 10-4
Correct answer is C
\(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\) = \(\frac{324 \times 10^{-4} \times 10^{-5}}{48 x 10^{-2} x 12 x 10^{-3}}\)
\(\frac{324 \times 64 \times 1 0^{-9}}{48 \times 12 \times 10^{-5}}\) = 36 x 10-4
= 3.6 x 10-3
If P = 18, Q = 21, R = -6 and S = -4, Calculate \(\frac{(P- Q)^3 + S^2}{R^3}\)
\(\frac{-11}{216}\)
\(\frac{11}{216}\)
\(\frac{-43}{116}\)
\(\frac{43}{116}\)
Correct answer is B
\(\frac{(P- Q)^3 + S^2}{R^3}\) = \(\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}\)
= \(\frac{-27 + 16}{R^3}\)
= \(\frac{-11}{-216}\)
= \(\frac{11}{216}\)
60
54
48
42
Correct answer is B
let x represent the total number of oranges shared, let the three boys be A, B and C respectively. A received \(\frac{1}{3}\) of x, Remainder = \(\frac{2}{3}\) of x . B received \(\frac{2}{3}\) of remainder (i.e.) \(\frac{2}{3}\) of x
∴ C received \(\frac{2}{3}\) of remainder (\(\frac{2}{3}\) of x) = 12
\(\frac{1}{3}\) x \(\frac{2x}{3}\) = 12
2x = 108
x = 54