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JAMB Mathematics Past Questions & Answers - Page 213

1,061.

A number of pencils were shared out among Bisi, Sola and Tunde in the ratio of 2 : 3 : 5 respectively. If Bisi got 5, how many were share out?

View answer & explanation

Correct answer is B

Let x r3epresent total number of pencils shared

B : S : T = 2 + 3 + 5 = 10

2 : 3 : 5

= $\frac{2}{10}$ x y

= 5

2y =5

2y = 50

∴ y = $\frac{50}{2}$

= 25

1,062.

Udoh deposited N150.00 in the bank. At the end of 5 years the simple interest on the principal was N55.00. At what rate per annum was the interest paid?

11%

7 $\frac{1}{3}$ %

3 $\frac{1}{2}$ %

View answer & explanation

Correct answer is B

S.I = $\frac{PTR}{100}$

R = $\frac{100}{PT}$

$\frac{100 \times 50}{150 \times 6}$ = $\frac{22}{3}$

= 7 $\frac{1}{3}$ %

1,063.

Simplify $\frac{0.0324 \times 0.00064}{0.48 \times 0.012}$

3.6 x 10²

3.6 x 10^-2

3.6 x 10^-3

3.6 x 10^-4

View answer & explanation

Correct answer is C

$\frac{0.0324 \times 0.00064}{0.48 \times 0.012}$ = $\frac{324 \times 10^{-4} \times 10^{-5}}{48 x 10^{-2} x 12 x 10^{-3}}$

$\frac{324 \times 64 \times 1 0^{-9}}{48 \times 12 \times 10^{-5}}$ = 36 x 10^-4

= 3.6 x 10^-3

1,064.

If P = 18, Q = 21, R = -6 and S = -4, Calculate $\frac{(P- Q)^3 + S^2}{R^3}$

$\frac{-11}{216}$

$\frac{11}{216}$

$\frac{-43}{116}$

$\frac{43}{116}$

View answer & explanation

Correct answer is B

$\frac{(P- Q)^3 + S^2}{R^3}$ = $\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}$

= $\frac{-27 + 16}{R^3}$

= $\frac{-11}{-216}$

= $\frac{11}{216}$

1,065.

Three boys shared some oranges. The first received $\frac{1}{3}$ of the oranges, the second received $\frac{2}{3}$ of the remainder. If the third boy received the remaining 12 oranges, how many oranges did they share?

View answer & explanation

Correct answer is B

let x represent the total number of oranges shared, let the three boys be A, B and C respectively. A received $\frac{1}{3}$ of x, Remainder = $\frac{2}{3}$ of x . B received $\frac{2}{3}$ of remainder (i.e.) $\frac{2}{3}$ of x

∴ C received $\frac{2}{3}$ of remainder ( $\frac{2}{3}$ of x) = 12

$\frac{1}{3}$ x $\frac{2x}{3}$ = 12

2x = 108

x = 54