\(\frac{-11}{216}\)
\(\frac{11}{216}\)
\(\frac{-43}{116}\)
\(\frac{43}{116}\)
Correct answer is B
\(\frac{(P- Q)^3 + S^2}{R^3}\) = \(\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}\)
= \(\frac{-27 + 16}{R^3}\)
= \(\frac{-11}{-216}\)
= \(\frac{11}{216}\)
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