In the diagram, angle QPR = 90o, angle PSR = 90o and PR = 5 units. Find the length of QS.
5 tan 25o sin 65o
5 cos 25o sin 65o
5 tan 25o cos 65o
cos 25o cos 65o
5 cosec 25o
Correct answer is C
From △QPR, < R = 180o - (25o + 90o)
180o - 115o = 65o
From △PSQ, Sin 65o = QPRhyp = PS5
PS = 5 sin 65o
From △PSR, tan = OPPadj = PSQS
but PS = 5 sin 65o
QS tan 25o = PS
QS tan 25o = 5 sin 65o
QS = 5sin65otan25o
= 5 tan 25o cos 65o
In the figure, WU//YZ, WY//YZ = 12cm, VZ = 6cm, XU = 8cm. Determine the length of WU.
1cm``3cm
6cm
2cm
4cm
Correct answer is D
From similar triangle, x6 = 812
12x = 48
x = 4812
= 4
12cm2
2812cm2
16cm2
10cm2
6cm2
Correct answer is E
Area of the triangle XYZ = 12bh = 12ZY x XY
= 12 x 3 x 4
= 6cm2.
In the figure, find x in terms of a, b and c.
a + b + c
180o - (a + b + c)
a - b - c
a + b
a + c
Correct answer is A
180 - x + a + b + c
= 180(sum of interior angle in triangle)
a + b + c = x.