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In the diagram, angle QPR = 90o, angle PSR = 90
In the diagram, angle QPR = 90o, angle PSR = 90o and PR = 5 units. Find the length of QS.

In the diagram, angle QPR = 90o, angle PSR = 90o and PR = 5 units. Find the length of QS.

A.

5 tan 25o sin 65o

B.

5 cos 25o sin 65o

C.

5 tan 25o cos 65o

D.

cos 25o cos 65o

E.

5 cosec 25o

Correct answer is C

From \(\bigtriangleup\)QPR, < R = 180o - (25o + 90o)

180o - 115o = 65o

From \(\bigtriangleup\)PSQ, Sin 65o = \(\frac{QPR}{hyp}\) = \(\frac{PS}{5}\)

PS = 5 sin 65o

From \(\bigtriangleup\)PSR, tan = \(\frac{OPP}{adj}\) = \(\frac{PS}{QS}\)

but PS = 5 sin 65o

QS tan 25o = PS

QS tan 25o = 5 sin 65o

QS = \(\frac{5 sin 65^o}{tan 25^o}\)

= 5 tan 25o cos 65o