JAMB Mathematics Past Questions & Answers - Page 135

671.

In the diagram above, QR // TS, QR : TS = 2.3, Find the ratio of the area of triangle PQR to the area of the trapezium QRST.

A.

4:9

B.

4:5

C.

1:3

D.

2:3

Correct answer is B

h1 = \(\frac{h_1 + h_2}{1.5}\) = \(\frac{h_1}{h_2} = 2\)

\(\frac{A_{\bigtriangleup PQR}}{A_{TP(QRST)}} = \frac{\frac{1}{2} \times 2 \times h_1}{\frac{1}{2} \times h_2 (2 + 3)}\)

\(\frac{2}{5} \times \frac{h_1}{h_2} = \frac{2}{5} \times 2\)

= \(\frac{4}{5}\)

672.

In the diagram, POQ is a diameter, 0 is the centre of the circle and TP is a tangent. Find the value of x

A.

30o

B.

40o

C.

45o

D.

50o

Correct answer is A

From the diagram, POQ is a diameter; o is the centre of the circle and TP is a tangent where RTP = 30o

RTP = RQP = x(at circumference = made by tangent outside the circle) i.e x = 30o

673.

An (\(n - 2)^2\) sided figure has n diagonals. Find the number n diagonals for a 25-sided figure

A.

7

B.

8

C.

9

D.

10

Correct answer is A

(n-2)\(^2\)=25

n - 2 = 5

n = 5 + 2 = 7

674.

In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \(\theta\)oand RQP = \(\phi\)o, which of the following relationships between \(\theta\)o and \(\phi\)o is correct

A.

\(\theta\)o + \(\phi\)o = 902

B.

\(\phi\)o = 902 - 2\(\theta\)o

C.

\(\theta\)o = \(\phi\)o

D.

\(\phi\)o = 2\(\theta\)o

E.

\(\theta\)o + 2\(\phi\)o

Correct answer is E

180 - \(\phi\)o = \(\theta\)o + \(\phi\)o (Sum of opposite interior angle equal to its exterior angle)

180 = 2\(\phi\) + \(\theta\)o

675.

In the figure, GHIJKLMN is a cube of side a. Find the length of HN.

A.

\(\sqrt{3a}\)

B.

3a

C.

3a2

D.

a\(\sqrt{2}\)

E.

a\(\sqrt{3}\)

Correct answer is E

HJ2 = a2 + a2 = 2a2

HJ = \(\sqrt{2a^2} = a \sqrt{2}\)

HN2 = a2 + (a\(\sqrt{2}\))2 = a2 + 2a2 = 3a2

HN = \(\sqrt{3a^2}\)

= a\(\sqrt{3}\)cm