In the figure, find PRQ
66\(\frac{1}{2}\)o
62\(\frac{1}{2}\)o
125o
105o
65o
Correct answer is B
Angle subtended at any part of the circumference of the circle \(\frac{125^o}{2}\) at centre = 360o - 235o = 125o
\(\bar{PQR}\) = \(\frac{125}{2}\)
= 62\(\frac{1}{2}\)o