Given that A = {3, 4, 1, 10, ⅓ }
B = {4, 3,⅓, ⅓, 7}.
Find A∩B
{}
{⅓, 1, 2}
{3, 4, ⅓}
{1, 3, ⅓}
Correct answer is C
A ∩ B = {3, 4, ⅓}
Simplify [1÷(x2+3x+2)]+[1÷(x2+5x+6)]
2(x+1)2
2(x+1)(x+2
2(x+1)(x+2
2(x+1)(x+3
Correct answer is D
[1÷(x2+3x+2)]+[1÷(x2+5x+6)]
= 1÷(x2+3x+2)+[1÷(x2+5x+6)]
= [1÷((x2+x)+(2x+2))]+[1÷((x2+3x)+(2x+6))]
= [1 ÷ (x(x + 2) + 2(x +1))] + [1 ÷ (x(x + 3) +2(x + 3) )]
= [1 ÷ (x + 1)(x + 2)] + [1 ÷ ((x + 3) + (x + 2))]
=((x + 3) + (x + 1)) ÷ (x + 1)(x + 2)(x + 3)
Using the L.C.M
=((x + x + 3 + 1)) ÷ (x + 1)(x + 2)(x + 3)
=(2x+4)/(x+1)(x+2)(x+3) =2(x+2)/(x+1)(x+2)(x+3)
= 2(x+1)(x+3)
Simplify (0.09)2 and give your answer correct to 4 significant figures
0.81
0.081
0.0081
8.0001
Correct answer is C
(0.09)2 = 0.09 × 0.09
= 0.0081
= 0.008100 to 4 significant figures
Please, start counting first from the non-zero digits i.e. 8
Find the simple interest on N325 in 5years at 3% per annum.
N48.75K
N50.10K
N75.50K
N15.75K
Correct answer is A
I =[ PRT ÷ 100]
[(325 × 5 × 3) ÷ (100)]
N(195 ÷ 4)
N48.75K