One bag contain 3 blue and 5 red balls, another bag contain 2 blue and 4 red balls respectively. One ball is drawn for each bag. What is the probability both balls are blue
\( \frac{2}{15} \)
\( \frac{3}{24} \)
\( \frac{3}{21} \)
\( \frac{3}{28} \)
Correct answer is B
No explanation has been provided for this answer.