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Points P and Q respectively 24m north and 7m east point R...

Points P and Q respectively 24m north and 7m east point R. What is the bearing of Q from P to the nearest whole degree?

A.

16o

B.

17o

C.

73o

D.

106o

E.

164o

Correct answer is E

Using pythagoras' theorem:

Hyp2 = Adj2 + Opp2 → 242 + 72

Hyp = √625 → 25

tanP=724

tanP=0.2917

P=tan1(0.2917)

= 16.26° 

Bearing of Q from P = 180° - 16.26°

= 163.74° 164°