\(\frac{2x^2 - 3x - 4}{(x-2)(x+3)}\)
\(\frac{2x^2 + 3x - 4}{(x-2)(x+3)}\)
\(\frac{2}{(x-2)(x+3)}\)
\(\frac{ 3x + 4}{(x-2)(x+3)}\)
\(\frac{3x - 4}{(x-2)(x+3)}\)
Correct answer is D
\(\frac{x}{x-2}-\frac{x+2}{x+3}\)
\(\frac{[x][x+3] - [x+2][x-2]}{[x-2][x+3]}\)
= \(\frac{x^2 + 3x - x^2 - 4}{[x-2][x+3]}\)
= \(\frac{3x - 4}{[x-2][x+3]}\)
Given that (3 - y) ÷ 2x = (6y + 7) ÷ (4x - 5), find the value of x when y = 2 ...
The histogram shows the age distribution of members of a club. What is their modal age? ...
An equilateral triangle of side √3cm is inscribed in a circle. Find the radius of the circle. ...
In diagram, PQ || ST and < PQR = 120o, < RST = 130o, find the angle marked x ...