θ = 223^o, 305^o
θ = 210^o, 330^o
θ = 185^o, 345^o
θ = 218^o, 323^o
Correct answer is D
On the y-axis, each box is \frac{1 - 0}{5} = \frac{1}{5} = 0.2unit
On the x-axis, each box is \frac{90 - 0}{6} = \frac{90}{6} = 15^o
⇒ θ_1 = 180^o + (2.5\times15^o) = 180^o + 37.5^o = 217.5^o ≃ 218^o (2 and half boxes were counted to the right of 180^o)
⇒ θ_2 = 270^o + (3.5\times15^o) = 270^o + 52.5^o = 322.5^o ≃ 323^o (3 and half boxes were counted to the right of 270^o)
∴ θ = 218^o, 323^o
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