In a basket, there are 6 grapes, 11 bananas and 13 orange...
In a basket, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random. What is the probability that the fruit is either a grape or a banana
6/30
5/30
17/30
11/30
Correct answer is C
Total fruits 6 + 11 + 13 = 30,
prob. (Grape) = \(\frac{6}{30}\)
prob. (Banana) = \(\frac{11}{30}\)
= \(\frac{11}{30}\) + \(\frac{6}{30}\) = \(\frac{17}{30}\)