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If cosθ = ab, find 1 + tan2...

If cosθ = ab, find 1 + tan2θ

A.

b2a2

B.

a2b2

C.

a2+b2b2a2

D.

2a2+b2a2+b2

Correct answer is A

cosθ = ab, Sinθ = b2a2a

Tanθ = b2a2a2, Tan 2 = b2a2a2

1 + tan2θ = 1 + b2a2a2

= a2+b2a2a2

= b2a2