b2a2
a2b2
a2+b2b2−a2
2a2+b2a2+b2
Correct answer is A
cosθ = ab, Sinθ = √b2−a2a
Tanθ = √b2−a2a2, Tan 2 = √b2−a2a2
1 + tan2θ = 1 + b2−a2a2
= a2+b2−a2a2
= b2a2
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