A box contains 5 red, 3 green and 4 blue balls. A boy is allowed to take away two balls from the box. What is the probability that the two balls are red?

A.

\(\frac{5}{33}\)

B.

\(\frac{5}{36}\)

C.

\(\frac{103}{132}\)

D.

\(\frac{31}{36}\)

Correct answer is A

Total number of balls = 5 + 3 + 4 

= 12 balls

P(first ball is red) = \(\frac{5}{12}\)

P(second ball is red) = \(\frac{4}{11}\)

\(\therefore\) P(both balls are red) = \(\frac{5}{12} \times \frac{4}{11}\)

= \(\frac{5}{33}\)