2[1+3m]
2[1-3m]
2[1-3m\(^2\)]
2[1+3m\(^2\)]
Correct answer is B
\(\frac{2-18m^2}{1+3m}\) = \(\frac{2[1-9m^2]}{1+3m}\)
\(\frac{2[1-3m][1+3m]}{1+3m}\)
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