If y = x2 - x - 12, find the range of values of x fo...
If y = x2 - x - 12, find the range of values of x for which y ≥ 0
x < -3 0r x > 4
x ≤ -3 or x ≥ 4
-3 < x ≥ 4
-3 ≤ x ≤ 4
Correct answer is B
y = x2 - x - 12
= (x - 4)(x + 3)
∴ x = 4 or x = -3
Checking the cases for y ≥ 0
We check values on the range x - 4 ≥ 0; x + 3 ≤ 0; x - 4 ≤ 0 and x + 3 ≥ 0 for the range which satisfies the inequality x2 - x - 12 ≥ 0.
We find that the inequality is satisfied on the range x ≤ -3 and x ≥ 4.
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